200 Divided By 1 4
| 78. | What will be residuum when 17200 is divided by 18 ? | |||||||
Answer: Option C Explanation: When n is even. (10 n - a n ) is completely divisibly by (x + a) (17200 - 1200) is completely divisible by (17 + 1), i.e., 18. |
| Akhil said: (Nov thirteen, 2011) | |
| Why cant information technology exist (17^200-ii^200) is completely divisible by 17+2=xix ? | |
| Gururaj said: (Mar half-dozen, 2013) | |
| Uncomplicated way way is: 17 ^2 %18 =one. (17^2)*(7^100) %18 will as well exist 1. | |
| Siddeswara Reddy said: (Jun 14, 2014) | |
| When (10-1)^north is divided past X then R=i, If northward is fifty-fifty natural number and if n is odd natural number then R = X-1. | |
| Swapnil said: (Jul 11, 2014) | |
| How can nosotros write 17^200-1^200 this one is not equals to 17^200. Nosotros tin write eighteen as 17+1 just why nosotros take 17^200-1. | |
| Anusha said: (Nov one, 2014) | |
| (17*17*17*......*17) /18. 18-17 = i. (-1*-ane*-1*.....*-ane) /18. Ability is still, 1/18. Respond is i (numerator). | |
| Prasanna Kartik said: (Jul 8, 2015) | |
| Hello guys, Nosotros can solve information technology by negative reminders concept. Here is our question 17^200 is divided past eighteen. 17/18 negative reminder is -ane. So (-1) ^200=ane. Instance xi/3 positive reminder equally we know is two and the negative reminder is -i(eleven-12). | |
| Gaurav said: (Feb 28, 2016) | |
| eleven/3 reminder is 2 merely what is -1(11-12)? Please explain more. | |
| Bharath said: (Aug thirty, 2016) | |
| 17^200 = (eighteen - ane)^200 gives (18^200) - 2 * eighteen + one which give remainder i when divided by 18. | |
| Mir Rokon Uddin said: (January ten, 2017) | |
| Information technology is notable that the ability of 17 is even. So we can consider 17^2 and divide it by 18. And we got 1 equally a reminder. And then the answer is 1. | |
| Dev said: (Mar 23, 2017) | |
| Please give me solution for finding the value of R. And explicate the reply. 26^57÷29 = R. | |
| Sweety said: (May 28, 2017) | |
| Delight, anyone explain this clearly. | |
| ESRAK AHMED KAFI said: (Jun 2, 2017) | |
| x^northward -1 is divisible past (X+1) when n is fifty-fifty. then, when we will split up 10^due north past (X+ane) the remainder will be definitely 1. Case: 2^2 =4, when 4 is divided by (two+1) i.east. iii, then the remainder volition be one. | |
| Shubham said: (Jun 29, 2017) | |
| Can somebody give all the partitioning rules for term (ten^n - a^n). | |
| Bhavesh Sharma said: (Jul five, 2017) | |
| I have more uncomplicated solution: 17^2 divided by 1 then the remainder is 1. Then we tin write 17^200 as( 17^2)^100. So nosotros get 1 remainder. | |
| Manoranjan Sahoo said: (Jul 1, 2018) | |
| (17^199+17)/18, (17^199+ane)/18 is completely divisible, and the reminder is sixteen. | |
| Rounak said: (Aug nineteen, 2018) | |
| What to do when n is odd number? | |
| Gopi said: (Jan 25, 2019) | |
| 17^200 - 1 = 18 * quotient. So, 17^200 = 18 * quotient + 1. We take taken that 1 as a reminder in all type of problems. And then, ans = ane. | |
| Praful Kumar said: (Mar 9, 2019) | |
| @All. Uncomplicated, it is solved by; Rule1: If a^even no. ÷ a+1, then the remainder will always be ane. | |
| Hamsa said: (Oct 30, 2019) | |
| What is the balance when 79^59 is divided by 40. | |
| Sekhar said: (February xvi, 2020) | |
| What is the residuum when 83^63 is divided by fourteen. | |
| Ravikumar Chauhan said: (April 7, 2020) | |
| But from where 1^200 come up? 17^200 is same or has the same value 17^200-1^200. Please explain. | |
| Lakshmi said: (May 29, 2020) | |
| I don't understand, please explicate it. | |
| Kaveri said: (Oct 5, 2020) | |
| When 17^200 is completely divisible by 18 and so the remainder needs to exist 0 right, then how come ane? | |
| Jigsa said: (April 3, 2021) | |
| x^northward +1 is divisible by (X+ane) when due north is odd. | |
| HRK said: (Sep 1, 2021) | |
| @All. the Elementary logic is; Given a number in the question is divisible past 2 as it will take 0 in the unit of measurement digit. To arrive divisible add 1 in the unit digit, i.due east. ane+7+1 (the number be similar 170000.....1) | |
| Meezab E Rehmat said: (Dec 27, 2021) | |
| @All. Here, -1 ways ane is the balance. And 18=17+1. | |
| Samridhi Shah said: (Aug 26, 2022) | |
| What if the power was odd no, for ex 17 ability 137? How to solve that? | |
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200 Divided By 1 4,
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(17200 - 1) is completely divisible by xviii.
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